(7x+8x)^0=1

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Solution for (7x+8x)^0=1 equation: 



(7x+8x)^0=1

We move all terms to the left:

(7x+8x)^0-(1)=0

We add all the numbers together, and all the variables

(+15x)^0-1=0

We move all terms containing x to the left, all other terms to the right

(+15x)^0=1

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